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Your data matches 1 statistic following compositions of up to 3 maps.
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Matching statistic: St000850
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Values
([],2)
=> 1
([(0,1)],2)
=> 0
([],3)
=> 3
([(1,2)],3)
=> 0
([(0,1),(0,2)],3)
=> 1
([(0,2),(2,1)],3)
=> 0
([(0,2),(1,2)],3)
=> 1
([],4)
=> 6
([(2,3)],4)
=> 1
([(1,2),(1,3)],4)
=> 1
([(0,1),(0,2),(0,3)],4)
=> 3
([(0,2),(0,3),(3,1)],4)
=> 0
([(0,1),(0,2),(1,3),(2,3)],4)
=> 1
([(1,2),(2,3)],4)
=> 1
([(0,3),(3,1),(3,2)],4)
=> 1
([(1,3),(2,3)],4)
=> 1
([(0,3),(1,3),(3,2)],4)
=> 1
([(0,3),(1,3),(2,3)],4)
=> 3
([(0,3),(1,2)],4)
=> 2
([(0,3),(1,2),(1,3)],4)
=> 0
([(0,2),(0,3),(1,2),(1,3)],4)
=> 2
([(0,3),(2,1),(3,2)],4)
=> 0
([(0,3),(1,2),(2,3)],4)
=> 0
([],5)
=> 10
([(3,4)],5)
=> 3
([(2,3),(2,4)],5)
=> 2
([(1,2),(1,3),(1,4)],5)
=> 3
([(0,1),(0,2),(0,3),(0,4)],5)
=> 6
([(0,2),(0,3),(0,4),(4,1)],5)
=> 1
([(0,1),(0,2),(0,3),(2,4),(3,4)],5)
=> 1
([(0,1),(0,2),(0,3),(1,4),(2,4),(3,4)],5)
=> 3
([(1,3),(1,4),(4,2)],5)
=> 0
([(0,3),(0,4),(4,1),(4,2)],5)
=> 1
([(1,2),(1,3),(2,4),(3,4)],5)
=> 3
([(0,2),(0,3),(2,4),(3,4),(4,1)],5)
=> 1
([(0,3),(0,4),(3,2),(4,1)],5)
=> 2
([(0,2),(0,3),(2,4),(3,1),(3,4)],5)
=> 0
([(0,1),(0,2),(1,3),(1,4),(2,3),(2,4)],5)
=> 2
([(2,3),(3,4)],5)
=> 3
([(1,4),(4,2),(4,3)],5)
=> 1
([(0,4),(4,1),(4,2),(4,3)],5)
=> 3
([(2,4),(3,4)],5)
=> 2
([(1,4),(2,4),(4,3)],5)
=> 1
([(0,4),(1,4),(4,2),(4,3)],5)
=> 2
([(1,4),(2,4),(3,4)],5)
=> 3
([(0,4),(1,4),(2,4),(4,3)],5)
=> 3
([(0,4),(1,4),(2,4),(3,4)],5)
=> 6
([(0,4),(1,4),(2,3)],5)
=> 1
([(0,4),(1,3),(2,3),(2,4)],5)
=> 2
([(0,4),(1,3),(1,4),(2,3),(2,4)],5)
=> 1
Description
The number of 1/2-balanced pairs in a poset.
A pair of elements $x,y$ of a poset is $\alpha$-balanced if the proportion of linear extensions where $x$ comes before $y$ is between $\alpha$ and $1-\alpha$.
Kislitsyn [1] conjectured that every poset which is not a chain has a $1/3$-balanced pair. Brightwell, Felsner and Trotter [2] show that at least a $(1-\sqrt 5)/10$-balanced pair exists in posets which are not chains.
Olson and Sagan [3] exhibit various posets that have a $1/2$-balanced pair.
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